1.

In the Q.23, the angle of projection with the horizontal is:-

Answer»

`TAN^(-1)((4)/(5))`
`tan^(-1)((5)/(4))`
`tan^(-1)((5)/(8))`
`tan^(-1)((8)/(5))`

Solution :`because u_(x)=40` and `u_(y)=25`
`THEREFORE tan THETA=(u_(y))/(u_(x))=(25)/(40)=(5)/(8)`


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