1.

In the Q.23, the maximum height attained by the arrow is:-

Answer»

25m
40m
31.25m
12.5m

Solution :`H=(1)/(2)"gt"^(2)=(1)/(2)xx10xx[(5)/(2)]^(2)=31.25m`
[time for downward journey `=(T)/(2)=(5)/(2)`]
In this time it will fall a DISTANCE equal to MAXIMUM height.


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