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In the question number 18, the potential at a point 20 cm from the mid-point of the line joining the two charges in a plance normal to the line and passing through the mid-point is |
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Answer» `1.4xx10^(5)V` `=1/(4piepsilon_0(PA))(q_1+q_2)` `(because PA=PB=sqrt((0.2)^2+(0.2)^2)=0.28 m) =(9xx10^9(1.8+2.8)xx10^(-6))/0.28=1.4xx10^5` V 
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