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In the question number 30, the net power absorbed by the circuit in one complete cycle isA. 5 WB. 10 WC. 15 WD. zero

Answer» Correct Answer - D
As `P = V_("rms")I_("rms")cos phi`
In a pure capacitance circuit, the phase difference between alternating voltage and current is `pi//2` . Hence
`P = V_("rms")I_("rms")cos 90^(@) = 0`.


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