1.

In the question number 33, find the wavelength of the incident light if the stopping potential is 0.6 V.

Answer»

326 nm
454 nm
524 nm
232 nm

Solution :(b) : According to EINSTEIN's photoelectric EQUATION
`eV_(0)=hv-phi_(0)=(hc)/(lamda)-phi_(0)""( :.v=(C)/(lamda))`
or `lamda=(hc)/((eV_(0)+phi_(0)))=(1242" EV "nm)/((0.6+2.14))~~454nm`


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