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In the question number 33, find the wavelength of the incident light if the stopping potential is 0.6 V. |
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Answer» 326 nm `eV_(0)=hv-phi_(0)=(hc)/(lamda)-phi_(0)""( :.v=(C)/(lamda))` or `lamda=(hc)/((eV_(0)+phi_(0)))=(1242" EV "nm)/((0.6+2.14))~~454nm` |
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