1.

In the question number 34, the kinetic energy (in MeV) of the proton beam produced by the accelerator is (radius of dees =60 cm)

Answer»

5
6.5
10.6
12.6

Solution :FINAL velocity of proton is
`v=rxx2 pi upsilon=0.6xx2xx3.14xx12xx10^(6)=4.5xx10^(7)"m s"^(-1)`
`therefore""K=(1)/(2)MV^(2)=(1)/(2)XX(1.67xx10^(-27)(4.5xx10^(7))^(2))/(1.6xx10^(-13))`
`="10.6 MEV"`


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