1.

In the question number 40, if velocity is normal in the shorter side then voltage developed is

Answer»

`2.3xx10^(-4)V`
`2.4xx10^(-4)V`
`4.8xx10^(-2)V`
`1.6xx10^(-2)V`

SOLUTION :Here, `l=2 cm =2XX10^(-2) m`

`epsi=Blv=0.4xx2xx10^(-2)xx2xx10^^(-2)=1.6xx10^(-4)V`


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