1.

In the question number 44, the phase difference between the voltage across the source and current is

Answer»

`80.2^(@)`
`31^(@)`
`50.2^(@)`
`38.2^(@)`

Solution :Here, `X_(L)-X_(C )=3.6Omega, R=6 Omega`
PHASE DIFFERENCE `phi = TAN^(-1)((X_(L)-X_(C ))/(R ))`
`therefore phi = tan^(-1)((3.6)/(6))=tan^(-1)(0.6)=31^(@)`


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