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in the question number 63, the frequency of emitted photon due to the given transition is (h=6.64xx10^(-34)Js,1eV=1.6xx10^(-19)J) |
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Answer» `2.46xx10^(10)Hz` `hupsilon=E_2=-E_1=10.2eV therefore upsilon=(10.2)/(h)EV` Here, `10.2eV=10.2xx1.6xx10^(-19)J,h=6.64xx10^(34)J_s` `therefore upsilon=(10xx1.6xx10^(-19))/(6.64xx10^(-34))=2.46xx10^(15)Hz`. |
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