1.

In the question number 67, find the potential energy of electron (in joule) in the given state.

Answer»

`-4.36xx10^(-14)J`
`-4.36xx10^(-16)J`
`-4.36xx10^(-17)J`
`-4.36xx10^(-18)J`

SOLUTION :As ,P.E.`=-2K.E`.
Here, `K.E.=13.6eV=2.18xx18xx10^(-18)J`
HENCE, P.E. `=-2xx2.18xx10^(-18)xx10^(-18)J=-4.36xx10^(-18)J`.


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