1.

In the reaction : 2Al(s) + 6HCl(aq) rarr 2 Al^(3+)(aq) + 6 Cl^(-)(aq) + 3H_(2)(g)

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Solution :`2Al(s) + 6HCL(AQ) rarr 2Al^(3+)(aq) + 6Cl^(-)(aq) + 3H_(2)(G) `
`:' 6 "mol es of HCl produce = 3 mol es of" H_(2) = 3 xx 22.4 L of H_(2) at S.T.P.`
`:'1 mol es of HCl p r o d u c e = 3 xx 22.4/6 Lof H_(2)at S.T.P. = 11.2 Lof H_(2) at S.T.P.`


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