1.

In the reaction, 3A rarr 2B rate of reaction, +(d[B])/(dt) is equal to

Answer»

`-1/3(d[A])/(dt)`
`-2/3(d[A])/(dt)`
`+(2D[A])/(dt)`
`-3/2(d[A])/(dt)`

Solution : In a REACTION,
`3Ararr2B`
RATE of reaction =`-1/3(d[A])/(dt)=+1/2(d[B])/(dt)`
`therefore (d[B])/(dt)=-2/3(d[A])/(dt)`


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