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In the reaction : 3Br_(2)+6CO_(3)^(2-)+3H_(2)Oto5Br^(-)+BrO_(3)^(-)+6HCO_(3)^(-) |
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Answer» Bromine is oxidised and CARBONATE is reduced `Zn(s)+2H^(+)(aq)toZn^(2+)(aq)+H_(2)(g)` `E=E^(@)-(RT)/(nF)"in "([Zn^(2+)](pH))/([H^(+)]^(2))` On adding `H_(2)SO_(4)`, the `[H^(+)]`increases . This will increases the value of E and , therefore reaction PROCEEDS more to the right. |
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