1.

In the reaction : 3BrO^(-)toBrO_(3)^(-)+2Br^(-) (aqueous alkaline medium at 80^(@)C) the value of the rate constant in the rate law in terms of -(d)/(dt)[BrO^(-)] is 0.056 Lmol^(-)s^(-1). What will be the rate constant when the rate law is stated in terms of (d)/(dt)[BrO_(3)^(-)] ?

Answer»

`18.7xx10^(-3)Lmol^(-1)s^(-1)`
`37.4xx10^(-3)Lmol^(-1)s^(-1)`
`0.08187Lmol^(-1)s^(-1)`
`18.7xx10^(-2)Lmol^(-1)s^(-1)`

ANSWER :C


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