

InterviewSolution
Saved Bookmarks
1. |
In the reaction `A^(+)+BtoA+B^(+)` there is no entropy change. If enthalpy change is 22 kJ of `A^(+)`, calculate `DeltaG` for the reaction. |
Answer» For the given reaction, `DeltaH=22kJ,DeltaS=0` `therefore` From `DeltaG=DeltaH-TDeltaS` `DeltaG=22-Txx0=22kJ" "mol^(-1)` |
|