1.

In the reaction `A^(+)+BtoA+B^(+)` there is no entropy change. If enthalpy change is 22 kJ of `A^(+)`, calculate `DeltaG` for the reaction.

Answer» For the given reaction,
`DeltaH=22kJ,DeltaS=0`
`therefore` From `DeltaG=DeltaH-TDeltaS`
`DeltaG=22-Txx0=22kJ" "mol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions