In the reaction `C(s) + CO_(2)(g)hArr2CO(g)` the following amounts of sbstance were formed in `0.2` litre flask `CO_(2) = 0.06` mole. The equilibrium constant isA. `0.208`B. `4.10`C. `0.30`D. `0.416`

In the reaction `C(s) + CO_(2)(g)hArr2CO(g)` the following amounts of

1.	In the reaction `C(s) + CO_(2)(g)hArr2CO(g)` the following amounts of sbstance were formed in `0.2` litre flask `CO_(2) = 0.06` mole. The equilibrium constant isA. `0.208`B. `4.10`C. `0.30`D. `0.416`
Answer» Correct Answer - A `K = ([CO]^(2))/([CO_(2)]) = (((0.05)/(0.2))^(2))/(((0.06)/(0.2))` `K = 0.208`

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In the reaction `C(s) + CO_(2)(g)hArr2CO(g)` the following amounts of sbstance were formed in `0.2` litre flask `CO_(2) = 0.06` mole. The equilibrium constant isA. `0.208`B. `4.10`C. `0.30`D. `0.416`

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