1.

In the reaction CH_(3) C -= C^(-) - Na^(+) +(CH_(3))_(2) CH - Cl to ? the product formed is .

Answer»

propene
propyne
propyne and propene
4 - methylpentyne - 2

Solution :`CH_(3) -UNDERSET (Cl) underset(|) CH - CH_(3)C -= C^(-) Na^(+) to`
`underset ("Propene") (CH_(3) - CH) = CH_(2) + underset ("Propyne")(CH_(3)C -= CH) + NaCl`


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