1.

In the reaction CH_(3)CH_(2)underset(Br)underset(|)(C)HCH_(2)CH=CH_(2)overset("KOH(alc.)")toA The product A is predominantly.

Answer»

`CH_(3)CH_(2)CH=CHCH=CH_(2)`
`CH_(3)CH=CHCH_(2)CH=CH_(2)`
`CH_(2)=CHCH_(2)CH_(2)CH=CH_(2)`
`CH_(3)CH_(2)CH_(2)CH_(2)C=CH`.

Solution :
Since the DOUBLE bonds are in conjugated POSITIONS the COMPOUND (A) is the most stable and is PREDOMINANTLY formed.


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