1.

In the reaction :Cl_(2)+2OH^(-)toOCl^(-)+Cl^(-)+H_(2)O

Answer»

`OH^(-)`is OXIDISING and `CL^(-)` is REDUCING agent
`Cl_(2)` is oxidising and `OH^(-)` is reducing agent
`OH^(-)`is both oxidising and reducing agent
`Cl_(2)`is both oxidising and reducing agent.

Solution :`Cl_(2)+2OH^(-)toOCl^(-)+Cl^(-)+H_(2)O`
O.N . Of Cl changes from 0 to +1 (in `Ocl^(-))and-1 "in" (Cl^(-))`.


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