1.

In the reaction , Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), the reduction half cell reaction is

Answer»

`Cu+2e^(-)rarrCu^(2+)`
`Cu-2e^(-)rarrCu^(2+)`
`AG^(+)+e^(-)rarrAg`
`Ag^(-)e^(-)rarrAg^(+)`

Solution :Copper UNDERGO oxdiation while SILVER `(Ag^(+))` undergo REDUCTION.


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