1.

In the reaction, H_(2)+I_(2)hArr 2.Hl. In a 2 litre flasek 0.4 moles of HI each H_(2) and I_(2) are taken. At equlibrium 0.5 moles of HI are formed. What will be the value of equilibrium constant, k_(c)

Answer»

`20.2`
`25.4`
`0.284`
`11.1`

SOLUTION :`{:(H_(2),+I_(2),hArr2HI),(0.4,0.4,0.50),(0.4-0.25=0.15//2,0.4-0.25=0.15//2,0.50//2):}`
`K_(C)=([H]^(2))/([H_(2)][I_(2)])=([(0.5)/(2)]^(2))/([(0.15)/(2)][(0.15)/(2)])=(0.5xx0.5)/(0.15xx0.15)=11.11`


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