1.

In the reaction: H_(2)S hArr 2H^(+) + S^(-), when NH_(4)OH is added, then

Answer»

`S^(--)` is precipitate
No reaction takes places
Concentration of `S^(--)` decreases
Concetration of `S^(-)` increases

Solution :In `IV^(th)` GROUP the `S^(2-)` concentration increase when ADDED the `NH_(4)OH` because
`NH_(4)OH hArr NH_(4)^(+) + OH^(-)`
`H_(2)S hArr 2H^(+) + S^(2-)`
`OH^(-) + H^(+) hArr H_(2)O`. So that `S^(2-)` is increased.


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