1.

In the reaction NaOH + Al(OH)_(3) ti NaAlO_(2) +H_(2)O The equivalent mass of Al(OH)_(3) is

Answer»

78
26
52
unpredictable

Solution :1 EQUIVALENT of NAOH = 1 equivalent of `Al(OH)_(3)`
`:. "40 g of NaOH"= (78)/(3) "g of "Al(OH)_(3)`
Hence equivalent mass of `Al(OH)_(3) = (78)/(3)=26 g`


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