In the reaction of canadium oxide (VO) with iron oxide `(Fe_2O_3)` the products are `V_2O_5` and `FeO`. How many grams of `V_2O_5` can be formed from 2.00 g of VO and 5.75 g of `Fe_2O_3`.

In the reaction of canadium oxide (VO) with iron oxide `(Fe_2O_3)` the

1.	In the reaction of canadium oxide (VO) with iron oxide `(Fe_2O_3)` the products are `V_2O_5` and `FeO`. How many grams of `V_2O_5` can be formed from 2.00 g of VO and 5.75 g of `Fe_2O_3`.
Answer» `2VO+3Fe_2O_3toV_2O_5+6FeO` Here `Fe_2O_3` is a limiting reagent. `3 " mol of "Fe_2O_3-=1 " mol of "V_2O_5` `(5.75)/(160)=0.036 " mol of "Fe_2O_3=(0.036)/(3)" mol of "V_2O_5` grams `V_2O_5=(0.036)/(3)xx181.9=2.182g`

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In the reaction of canadium oxide (VO) with iron oxide `(Fe_2O_3)` the products are `V_2O_5` and `FeO`. How many grams of `V_2O_5` can be formed from 2.00 g of VO and 5.75 g of `Fe_2O_3`.

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