1.

In the reaction Pb(s)+Cu^(2+) (aq) rarr Pb^(2+) (aq)+Cu(s) which is reducing agent

Answer»

`PB^(2+) (aq)`
`CU^(2+) (aq)`
`Pb(s)`
`Cu(s)`

Solution :`Pb_((s))` releases `2e^(-)` to form `Pb_((aq))^(2+)` and its O.N. INCREASES by 2, hence it is a reducing AGENT.


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