1.

In the reaction PbO_(2)+SO_(2) to PbSO_(4)

Answer»

Lead is REDUCED from `Pb^(4+)` to `Pb^(2+)`
`SO_(2)` is oxidised to sulphate
OXYGEN undergoes disporportionation
Pb is NEITHER oxidised nor reduced

Solution :`OVERSET(+4)(Pb)O_(2)+SO_(2)to overset(+2)(Pb)SO_(4)`


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