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Answer» (I) is the major elimination product (II) is formed at faster rate than (I) (I) is formed at faster rate than (II) increasing order of reactivity with different `X` is `FltCIltBrltI` . Solution :With ethoxide base most SUBSTITUTED alkene (I) is formed as the major product in the formation of (II) `C_(2)H_(5)O` takes proton from less hindered Beta -carbon HENCE less activation energy and greater rate of reaction althought stabilityof product determines it content at EQUILIBRIUM Also since `E2` reaction is an elementary reaction in which halogen leaves in the rate determining step iodide leaves most easily and fluoride with maximum difficulty .
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