1.

In the reactions C(s)+CO_(2)(g)hArr2CO(g) the equlibrium pressure is 12 atm. If 50% of the CO_(2) reacts, then

Answer»

`K_(p)` will be equal to 4
`K_(p)` will be equal to 16
The initial pressure =8
The partial pressure of CO is 8 atm atequlibrium

Solution :`K_(p)=(P_(CO)^(2))/(P_(CO_(2))),P_(CO_(2))+P_(CO)=12implies1/2P_(CO)+P_(CO)=12`
`[thereforeP_(CO_(2))=1/2P_(CO)]`
`3/2P_(CO)=12impliesP_(CO)=(2xx12)/(3)=8`
`impliesK_(p)=((P_(CO))^(2))/((P_(CO_(2))))=(8xx8)/(4)=16""["Initially only" CO_(2)` was present, therefore initial pressure =8]
Hence CHOICES (B), (c), (d) are correct while (a) is incorrect.


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