1.

In the region between the plane z=0 and z=a (a gt 0), the uniform electric and magnetic fields are given by vecE=E_(0)(hatk-hatj), vecB=B_(0)hati. The region defined by a le z le b contains only magnetic field vecB= -B_(0)hati. Beyond z gt b no field exits. A positive point charge q is projected from the origin with velocity v_(0)hatk. Assuming the mass of the particle to be (2)/(3)(qE_(0)a)/(v_(0)^(2)). When the particle just reverse its direction, all the fields are switched off. Time taken by the particle to touch the plane z=0 from that instant is

Answer»

`a//v_(0)`
`a//2v_(0)`
`(a)/(3v_(0))`
`(a)/(4v_(0))`

Solution :After the field are switched off, VELOCITY REMAINS constant


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