In the region between the plane z=0 and z=a (a gt 0), the uniform electric and magnetic fields are given by vecE=E_(0)(hatk-hatj), vecB=B_(0)hati. The region defined by a le z le b contains only magnetic field vecB= -B_(0)hati. Beyond z gt b no field exits. A positive point charge q is projected from the origin with velocity v_(0)hatk. Assuming the mass of the particle to be (2)/(3)(qE_(0)a)/(v_(0)^(2)). The minimum value of b such that the particle reverses its direction completely is

In the region between the plane z=0 and z=a (a gt 0), the uniform elec

1.	In the region between the plane z=0 and z=a (a gt 0), the uniform electric and magnetic fields are given by vecE=E_(0)(hatk-hatj), vecB=B_(0)hati. The region defined by a le z le b contains only magnetic field vecB= -B_(0)hati. Beyond z gt b no field exits. A positive point charge q is projected from the origin with velocity v_(0)hatk. Assuming the mass of the particle to be (2)/(3)(qE_(0)a)/(v_(0)^(2)). The minimum value of b such that the particle reverses its direction completely is
Answer» `(4E_(0)a)/(3v_(0)B_(0))` `a(1+(4E_(0))/(3v_(0)B_(0)))` `(2E_(0)a)/(3v_(0)B_(0))` `a(1+(2E_(0))/(3v_(0)B_(0)))` SOLUTION :`(B-a)` is the radius of the circle

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