1.

In the region between the plane z=0 and z=a (a gt 0), the uniform electric and magnetic fields are given by vecE=E_(0)(hatk-hatj), vecB=B_(0)hati. The region defined by a le z le b contains only magnetic field vecB= -B_(0)hati. Beyond z gt b no field exits. A positive point charge q is projected from the origin with velocity v_(0)hatk. Assuming the mass of the particle to be (2)/(3)(qE_(0)a)/(v_(0)^(2)). The value of E_(0) such that the particle moves undeviated upto the plane z=a is

Answer»

`(v_(0)B_(0))/(SQRT(2))`
`v_(0)B_(0)`
`v_(0)B_(0)sqrt(2)`
`(v_(0)B_(0))/(2)`

Solution :`qv_(0)B=qE_(0)rArrE_(0)=v_(0)B`


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