1.

In the reversible reaction, 2NO_(2)overset(k_(1))underset(k_(2))iff N_(2)O_(4), the rate of disppearance of NO_(2) is equal to

Answer»

`(2k_(1))/(k_(2))[NO_(2)]^(2)`
`2" k"_(1)[NO_(2)]^(2)-2" k"_(2)[N_(2)O_(4)]`
`2" k"_(1)[NO_(2)]^(2)-k_(2)[N_(2)O_(4)]`
`(2" k"_(1)-k_(2))[NO_(2)]`

SOLUTION :RATE of reaction `= -(1)/(2)(d[NO_(2)])/(DT)`
`=k_(1)[NO_(2)]^(2) -k_(2)[N_(2)O_(4)]`
`therefore` Rate of DISAPPERANCE of `NO_(2)`
`= (d[NO_(2)])/(dt) = 2 k_(1)[NO_(2)]^(2) - 2k_(2) [N_(2)O_(4)]`


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