1.

In the same time required for 5 litres of carbon monoxide to diffuse through a porous barrier, only 2 litres of an unknown gas will pass through . The molecular mass of unknown gas is :

Answer»

70
11.2
175
4.48

Solution :LET the time required is t.
`( rate ( CO_(2)))/( "rate( unknown gas )")= ( 5//t)/( 2 //t)`
`= sqrt(("M ( unknown gas)")/(44))`
`= ( 25)/( 4) = ( "M ( unknown gas)")/( 44)`
`:. ` M (unknown gas ) = `( 25 XX 44)/( 4) = 175`


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