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In the sequence of following nuclear reactions ._(92)X^(238) overset(-alpha)rarr Y overset(-beta)rarr Z overset(-beta)rarr L overset(-nalpha)rarr ._(84)M^(218) the value of n will be

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Solution :The VALUE of `n = (238 - 218)/(4) = (20)/(4) = 5 - 1 = 4`


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