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In the sequence of the following nuclear reaction ""_(98)^(238) X overset(-alpha)(to) Y overset(-beta)(to) Z overset(-beta) (to)Loverset(n alpha) (to) ""_(90)^(218) M What is the value of n |
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Answer» 3 `""_(98) Z^(234) to ""_(90) Na^(218) + N(""_(2) alpha^(4))` `234 = 218 + 4N implies n = ((234 - 218)/(4)) = 4 , 98 = 90 + 2N implies n = (8)/(2) = 4` |
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