1.

In the series LCR circuit shown the impedance is A. `200 Omega`B. `100 Omega`C. `300 Omega`D. `500 Omega`

Answer» Correct Answer - D
`X_(L) = 2pifL=2pi(50/pi) xx 1=100Omega`
`X_(C) = 1/(2pifC) = 1/(2pi(50/pi)20xx10^(-6)) = 500 Omega`
Impedance , `Z= sqrt(R^(2)+(X_(C)-X_(L))^(2)`
`rArr = Z = sqrt((300)^(2)+(400)^(2))` = `500Omega`


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