1.

In the shown circuit, all three capacitor are identical and have capacitance C mu F each. Each resistor has resistance of R Omega. An ideal cell of emf V volts is connected as shown. Then the magnitude of potential difference across cpacitor C_(3) in steady state is :

Answer»

`(V)/(3)`
`(V)/(2)`
`(2)/(9)V`
`(3)/(4)V`

SOLUTION :No current passes through CAPACITORS in steady state ASSUME potential at point `'4'` to be zero. Then points `'1'` and `'2'` are at same potential `(2V)/(3)` .
Hence `C_(1)` and `C_(2)` can be take in parallel.
The potential at point `3` is `(V)/(3)` .
`:.` Equivalent circuit of all three capacitors is show Hence potential difference across CAPACITOR `C_(3)` is
`=(2C)/(2C+C)xx((2V)/(3)-(V)/(3))=(2V)/(9)`


Discussion

No Comment Found

Related InterviewSolutions