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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:A. `3/23`B. `5/27`C. `7/29`D. `9/31`

Answer» Correct Answer - B
`1/lambda=RZ^(2)(1/n_(1)^(2)-1/n_(2)^(2))`
for longest wave length in Lyman series `n_(1)=1, n_(2)` and for Balmar series `n_(1), n_(2)=3`


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