In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series isA. `5//27`B. `1//93`C. `4//9`D. `3//2`

In the spectrum of hydrogen atom, the ratio of the longest wavelength

1.	In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series isA. `5//27`B. `1//93`C. `4//9`D. `3//2`
Answer» Correct Answer - A In Lyman series `lambda_(max) = (4)/(3R)` In Balmer series `lambda_(max) = (36)/(5R)`. So required ratio `= (5)/(27)`

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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series isA. `5//27`B. `1//93`C. `4//9`D. `3//2`

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