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In the standardization of Na_(2)S_(2)O_(3) using K_(2)Cr_(2)O_(7) by iodometry, the equivalent weight of K_(2)Cr_(2)O_(7) is |
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Answer» (MOLECULAR weight)/2 `K_(2)OVERSET(+6)(Cr_(2))O_(7)=("molecular weight")/(6)` |
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