1.

In the synthesis of ammonia by Haber process , if 60 moles of ammonia is obtained in one hour , then the rate of disapperance of Nitrogen is

Answer»

30 mol/min
6 mol/min
`0.5` mol/min
60 mol/min

SOLUTION :`N_(2) + 3H_(2) = 2NH_(3)`
rate = `- (d[N_(2)])/(dt) = -(1)/(3) (d[H_(2)])/(dt) = (1)/(2) (d[NH_(3)])/(dt)`
Rate of disappearance of `N_(2)`
`= (1)/(2)` of rate of formation of `NH_(3)`
`= (1)/(2) xx (60 "mole")/(1"hour")=(1)/(2) xx (60)/(60)` mole/minute
= 0.5 mole/minute .


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