1.

In the synthesis of ammonia from nitrogen and hydrogen gases, if 6xx10^(-2) mole of hydrogen disappears in 10 minutes, the number of moles of ammonia formed in 0.3 minutes is

Answer»

`1.8xx10^(-2)`
`1.2xx10^(-3)`
`4XX10^(-2)`
`3.6xx10^(-2)`

SOLUTION :`N_(2) + 3H_(2) to 2 NH_(3)`
Rate `= -(d[N_(2)])/(dt) = (6xx 10^(-2)mol)/(10 min) = 6 XX 10^(-3) mol min^(-1)`
Rate of formation of `NH_(3)`
`i.e., "" (d[NH_(3)])/(dt) = (2)/(3)(-(d[H_(2)])/(dt))`
`= (2)/(3) xx 6 xx 10^(-3) mol min^(-1)`
`= 4 xx 10^(-3) mol min^(-1)`
Now, if `dt = 0* 3 min`,
`NH_(3)` formed `= (4 xx 10^(-3) mol min^(-1))(0.3 min)`
`= 1. 2 xx 10^(-3) mol`


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