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InterviewSolution
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In the two block spring system, force constant of spring is k = 6N/m. Spring is stretched by 12 cm and then left. Match the following. |
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Answer» Correct Answer - `(A rarrq , B rarr s, C rarr p)` `omega=sqrt((k)/(mu))` Here, `mu`=reduced mass `=(m_(1)m_(2))/(m_(1)+m_(2))=(2)/(3)kg` `therefore omega=sqrt((6)/(2//3))=3 "rads"^(-1)` Amplitude 12 cm distance in inverse ratio of mass, `therefore A_(1)=8 cm` and `A_(2)=4 cm` Now, maximum kinetic energy `K_(1)=(1)/(2)m_(1)omegaA_(1)^(2)` `=(1)/(2)xx1xx3xx(8xx10^(-2))^(2)=9.6 mJ` `K_(2)=(1)/(2)xx2xx3xx(4xx10^(-2))^(2)=4.8 mJ` |
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