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In the Young's double slit experiment, the slits are 0.4 cm apart and the screen is 100 cm awayIf the wavelength of light used is 5000 Å then the distance between the fourth dark fringe and central bright will be ...... |
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Answer» `4.37xx10^(-2) CM` `d sin theta_(n)=(2n-1)(LAMBDA)/(2)` but `sin theta_(n)=(x_(n))/(D)` `:.(dx_(n))/(D)=(2n-1) (lambda)/(2)` `:.x_(n)=((2n-1)lambdaD)/(2d)`, here `n=4, d=0.4 cm` `lambda=5xx10^(-5)cm, D=100 cm and n=4` `:.x_(4)=(7lambdaD)/(2d)` `=(7xx5xx10^(-5)xx100)/(2xx0.4)` `:.x_(4)=4.37xx10^(-2) cm` |
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