1.

In thermodynamic process, pressure of a fixed mass of a gas is changes in such a manner that the gas molecules gives out 20 J of heat and 10 J of work is done in the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will beA. 30 JB. 20 JC. 60 JD. 40 J

Answer» Correct Answer - A
`DeltaQ=-20J,DeltaW=-10J,U_i=40J,U_f=?`
`DeltaQ=DeltaU+DeltaW=U_f-U_i+DeltaW`
`-20=U_f-40-10`
`U_f=30J`


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