In traingle ABC, angle bac =90,AD perpendicular bcDE perpendicular AB

1.	In traingle ABC, angle bac =90,AD perpendicular bcDE perpendicular AB DF perpendicular ac Prove that Area of AEDF=root(AE x eb x AF x fc) PLEASE Answer this..... I'll mark u as the branliest....... I'll follow u.....
Answer» Do you see that AEDF is a rectangle? Now its AREA is the multiplication of each breadth and height. Hint: The breadth and height is related to four triangles. The ratio of the two SIDES is equal. ΔAED ≈ ΔDEB → AE : ED = DE : EB ∴ED² = AE × EB, furthermore ED = √AE × EB ΔAFD ≈ ΔDFC → AF : FD = DF : FC ∴FD² = AF × FC, furthermore FD = √AF × FC ED × FD is the area of the rectangle. Now let's find the multiplication of both equations. → ED × FD = √AE × EB × AF × FC therefore PROVED.

In traingle ABC, angle bac =90,AD perpendicular bcDE perpendicular AB DF perpendicular ac Prove that Area of AEDF=root(AE x eb x AF x fc) PLEASE Answer this..... I'll mark u as the branliest....... I'll follow u.....

Answer»

Do you see that AEDF is a rectangle? Now its AREA is the multiplication of each breadth and height.

Hint: The breadth and height is related to four triangles.

The ratio of the two SIDES is equal.

ΔAED ≈ ΔDEB

→ AE : ED = DE : EB

∴ED² = AE × EB, furthermore ED = √AE × EB

ΔAFD ≈ ΔDFC

→ AF : FD = DF : FC

∴FD² = AF × FC, furthermore FD = √AF × FC

ED × FD is the area of the rectangle. Now let's find the multiplication of both equations.

→ ED × FD = √AE × EB × AF × FC therefore PROVED.

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In traingle ABC, angle bac =90,AD perpendicular bcDE perpendicular AB DF perpendicular ac Prove that Area of AEDF=root(AE x eb x AF x fc) PLEASE Answer this..... I'll mark u as the branliest....... I'll follow u..... ​