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In trapezium ABCD, side AB || side PQ|| side DC, AP = 15, PD = 12, QC = 14, find BQ. |
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Answer» Answer: In trapezium ABCD , Ap = 15 ; PD = 12 ; QC = 14 ---- given By b.p.t ( BASIS Proportionality Theorem ) Ap / PD = BQ / QC 15 / 12 = BQ / 14 12 BQ = 15 × 14 12 BQ = 210 . BQ = 210/ 12 BQ = 17.5 |
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