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In triangle ABC, AD perpendicular to BC. Prove that AB² - BD2² = AC²- CD² ?plz plz answer |
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Answer» There is a ∆ABC with AD as the perpendicularAB²-BD² = AC²-CD²We shall use the Pythagoras theorem on both the triangles and then equate the EQUATIONS we get from that to prove the GIVEN STATEMENT!!In ∆ADCIn ∆ADBAD² = AC² - CD²AD² = AB² - BD² |
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