In triangle ABC, Angle B=Angle C and ray AX bisects the exterior Angle

1.	In triangle ABC, Angle B=Angle C and ray AX bisects the exterior Angle DAC. If Angle DAX=70, then Angle ACB= *
Answer» Step-by-step EXPLANATION: Angle DAN=70 AN bistects angle DAD so, angle NAC =DAN=70 DB is a straight LINE, so angle DAB is 180 =>BAC+70+70=180 =>BAC=180-(70+70) =180-140 =40 given , angle B=C, Let them be x so, angle A+B+C=180(sum of ANGLES of a =>40+x+x=180 triangle is 180) => 2x=180-40 =>x=140/2 =70 Hence = 40,70,70.

In triangle ABC, Angle B=Angle C and ray AX bisects the exterior Angle DAC. If Angle DAX=70, then Angle ACB= *

Answer»

Step-by-step EXPLANATION:

Angle DAN=70

AN bistects angle DAD

so, angle NAC =DAN=70

DB is a straight LINE, so angle DAB is 180

=>BAC+70+70=180

=>BAC=180-(70+70)

=180-140

=40

given , angle B=C, Let them be x

so, angle A+B+C=180(sum of ANGLES of a

=>40+x+x=180 triangle is 180)

=> 2x=180-40

=>x=140/2

=70

Hence = 40,70,70.