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In $\triangle ABC$, $\angle C$ = $90^{0}$ and AB = c, BC = a, CA = b; then the value of (cosec B - cos A) is1). $\frac{c^{2}}{ab}$2). $\frac{b^{2}}{ca}$3). $\frac{a^{2}}{bc}$4). $\frac{bc}{a^{2}}$ |
Answer» ANSWER for this QUESTION is OPTION 3 | |